What are postfix operators in C++? (2024)

#include<iostream>using namespace std;int main() { int j = 0, i = 10; // If we assign j to be i++, j will take i's current // value and i's value will be increatemnted by 1. j = i++; cout << j << ", " << i << "\n"; return 0;}

10, 11

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In the context of the provided article snippet on postfix operators in C++, let me delve into the key concepts mentioned:

1. Postfix Operators in C++: Postfix operators are unary operators in C++ that operate on a single variable. Specifically, there are two postfix operators: ++ (increment) and -- (decrement). In the example provided, i++ is used, where the value of i is incremented, but the value of the expression is the original value of i. The postfix notation first assigns a value to the expression and then increments the variable.

2. Example Code:

   #include<iostream>
   using namespace std;
   
   int main() {
      int j = 0, i = 10;
      j = i++; // Assign j to be i++, j takes i's current value, and i's value is incremented by 1.
      cout << j << ", " << i << "\n";
      return 0;
   }

   Output: This will give the output − 10, 11

3. Explanation: The code demonstrates the use of the postfix operator i++. The value of j is assigned the current value of i, and then i is incremented by 1. Hence, the output is 10, 11.

4. Related Articles:

   • What are postfix operators in C#?
   • Difference between prefix and postfix operators in C#.
   • What is the difference between prefix and postfix operators in C++?
   • What are unary operators in C#?
   • What are increment (++) and decrement (--) operators in C#?

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