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SSC JE EE Previous Year Paper 14 (Held On: 26 Sep 2019 Morning)
- Neither bulb will glow
- The 60 W bulb will glow brighter
- The 100 W bulb will glow brighter
- Both will glow equally bright
Answer (Detailed Solution Below)
Option 3 : The 100 W bulb will glow brighter
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Download Solution PDFPower dissipation in a lamp,
\(P = \frac{{{V^2}}}{R}\)
Since both bulbs are rated at the same voltage, we can say that resistance of each bulb is inversely proportional to its rated power. Therefore, the resistance of 60 W bulb (R60) is greater than the resistance of 100 W (R100) bulb.
Since lamps connected in parallel, the voltage across theboth bulbis same.
The power dissipated across 60 W lamp,\({P_{60}} = \frac{{{V^2}}}{{{R_{60}}}}\)
The power dissipated across 100 W lamp, \({P_{100}} = \frac{{{V^2}}}{{{R_{100}}}}\)
As R60> R100, the power dissipated across 100W is greater than 60 W.
Hence 100 W bulb will glow brighter in parallel connection.
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